This is a place for the community of learners in Room 8-41 to learn and enjoy math. It is an extension of the classroom making it accessible 24 hours a day, 7 days a week.

## Tuesday, November 30, 2010

### Math Pages 125-127

-Means out of 100

-Another name for hundredths

-65% means 65 out of 100 or 65/100 or 0.65

Fractional Percent:

-A percent that includes a portion of a percent such as 7 3/8% or 4.5%

Page 125 Show you Know

A) 248%=

B) o.4%=

C) 74.8%=

Page 127 Show you Know

A)

B)

C)

## Thursday, November 18, 2010

### Duyen's Math Scribe Post: Pages 110 & 111 Questions 3, 9, 13

Sorry for the bad quality because when I converted the PowerPoint to AuthorStream then to Youtube, it just killed the original quality. Also if you notice the words might seem squished or cut well it's not. It's just that when AuthorStream converted the file it converted it to make it fit to a smaller screen. By the way it's suppose to have music, but it didn't work on Authorstream.

**Watch**http://www.youtube.com/watch?v=iFPsqk8MYj0

http://www.youtube.com/watch?v=FUhpIS8YTfc

http://www.youtube.com/watch?v=ku4rEwRxZOc

http://www.youtube.com/watch?v=kBw_i6tlQfU

Play

http://www.quia.com/jg/65631.html

http://resources.oswego.org/games/

Search

http://www.mathsisfun.com/square-root.html

http://staff.argyll.epsb.ca/jreed/math8/strand1/1105.htm

### Paulo's Textbook Post page 110-111 numbers 3 7 11

**Maria**walked

**4**

**20m**

**Walter**walked

**323m**

**Maria**walked

**97m**further.

**√159 = √a²**

**12.6 = a**

**minimum distance is 279**.1cm and the

**maximum distance is 291.7cm**

## Wednesday, November 17, 2010

### Raelynn's Homework Book Post: pg. 33 Numbers 4,6,7

Homework Book pg. 33

Numbers 4, 6, 7.

4.) The foot of a ladder is 1m from a wall. If the ladder is 6cm long, how far up the wall does the ladder reach? Give the answer to the nearest tenth of a metre. Show your work.

a² - b² = c²

6² - 1² = c²

(6x6) - (1x1) = c²

36cm² - 1cm² = 35 cm²

35cm² = c²

√35cm² = √c²

5.9cm² = c² (round up will be 6)

It will be 5.9/6 far up the wall.

6.) The width of a rectangle is 8cm, and its diagonal is 17cm.

a) Calculate the length of the rectangle. Show your work.

c² - b² = a²

17² - 8² = a²

(17x17) - (8x8) = a²

289cm² - 64cm² = 225cm²

225cm² = c²

√225cm² = √c²

15cm² = c²

b) Calculate the area of the rectangle.

120cm²

7.) A quadrilateral has a width of 17cm and a length of 26cm. A diagonal is 31cm. Is the quadrilateral a rectangle? Justify your answer.

a² + b² = c²

26² + 17² = c²

(26x26) + (17x17) = c²

676cm² + 289cm² = 965cm²

965cm² = c²

√965cm² = √c²

31.06cm²

Answer: No, the corners do not meet at right angles because 17² + 26² ≠ 31²

Enjoy this video. Hope it helps.

## Tuesday, November 16, 2010

### Shane's Textbook Post Pages 103-105. Numbers 7,10,13,15

a.)

h² + 5² = 9²

h² = 9² - 5²

h² = (9x9) - (5x5)

= 81-25 = 56

= √h² = √56 mm²

= h = 7.48 mm

p² + q² = r²

p² + 11² = 15²

p² = 15² - 11²p

p² = (15x15) - (11x11)

= 225 - 121 = 104

= √p² = √104 mm²

= 10.20

a² + b² = c²

27 m² + 27 m² = c²

(27x27) + (27x27)

729 + 729 = c²

1458 m²

√1458 m² = √c²

38.18 m²

a² + b² = c²

8² + b² = 10 mm

b² = 10² - 8²

b² = (10x10) - (8x8)

= 100 - 64 = 36

= √b² = √36 mm²

= b = 6 mm

a² + b² = c²

=22 + 42 = c²

=4 + 16 = c²

=20 = c²

The square root of 20 = c²

c² = 4.47

### Homework Book : Even Questions

a² = 26² - 24²

a² = 676 - 576

a² = 100m²

√100m² = √a²

10m = a

b) b² = c² - a²

b² = 39² - 15²

b² = 1521 - 225

b² = 1296cm²

√1296cm² = √b²

36cm = b

a) a² + b² = c²

8² + 9² = c²

64 + 81 = c²

145cm² = c²

√145cm² = √c²

12cm = c

b) a² + b² = c²

6² + 10² = c²

36 + 100 = c²

136cm² = c²

√136cm² = √c²

12cm = c

I thought of the height as the line going upwards↑, the base as the bottom_, and the hypotenuse is the longest leg. I used B as the unknown height.

b² = c² - a²

b² = 11² - 4²

b² = 121 - 16

b² = 105cm²

√b² = √105cm²

b = 10.2m

No the ramp is not a right triangle because the areas of the legs added up to 13m². The area of the hypotenuse on the other hand was 25m². For the shape to be a right triangle the two values would have to be equal.

Here is a video and a link to a fun-filled Pythagoras game. ←Click that for the game ☺

P.S if you see a √ its a square root symbol.

### Trisha's Textbook pages (:

# 6, 9, 12 and 15

6. Determine the length of the leg for each right triangle.

a)

a2 + b2 = c2

72 + 252 = c2

49 + 625 = c2

674 =c2

The square root of 674cm = c2

25.96 cm = c

b)

T2 - S2 = R2

262 - 242 = R2

676 - 576 =R2

100 = R2

10cm = R2

9. Tina wants to construct a path along the diagonal of her yard. What length will the path be? Express your answer to the nearest tenth of a meter.

a2 + b2 = c2

62 + 122 = c2

36 + 144 = c2

180 = c2

The square root of 180 = c2

13.41 = c

12. The hypotenuse of the triangle cuts the circle in half. What is the diameter of the circle?

a2 + b2 = c2

72 + 52 = c2

49 + 25 = c2

74 = c2

The square root of 74 = c2

8. 60

15. The coordinate grid shown was drawn centimeter grid paper. What is the length of lime segment AB?

A and B segment looks like a right triangle.

a2 + b2 = c2

22 + 42 = c2

4 + 16 = c2

20 = c2

The square root of 20 = c2

4.47 = c

Special thanks to Anabelle for helping me out (:

Thanks.

### Patrick's Textbook Post Pages 103-105. Numbers 5,8,11,14

area of square = a²

area of square = 6x6

area of square = 36cm²

### Homework Book: Odd Questions

of a right triangle when the lengths of the two_______ are known.

pythagorean, lengths, hypotenuse, legs

3)Determine the length of each hypotenuse.show your work.

A)

a²+b²=c²

9cm²+40cm²=c²

9x9+40x40=c²

81cm²+1600cm²=c²

1681cm²=c²

√1681cm²=√c²

41cm=c

B)

a²+b²=c²

12m²+35m²=c²

12x12+35x35=c²

144m²+1225m=c²

1369m²=c²

√1369m²=√c²

37m=c

5)Calculate the missing side length for each right triangle, to the nearest tenth of a centimetre. Show your work.

A)

c²-a²=b²

6cm²-5cm²=b²

6x6+5x5=b²

36cm²+25cm²=b²

11cm²=b²

√11cm²=√b²

3.3cm=b

B)

c²-b²=a²

12cm²-7cm²=a²

12x12+7x7=a²

144cm²+49cm²=a²

95cm²=a²

√95cm²=√a²

9.7cm=a

7)A triangle is made up of two smaller congruent right triangles.

A)Find the length of the hypotenuse for the right triangles, to the nearest tenth of a metre. Show your work.

a/2=a²

8/2=4

a²+b²=c²

4²+2²=c²

4x4+2x2=c²

16m²+4m²=c²

20m²=c²

√20m²=√c²

4.5m=c

B)Calculate the perimeter of the large triangle, to the nearest tenth of a metre. Show your work.

a+b=perimeter

8+4.5=17 m

Here is a link about Pythagorean Relationship.

Here is a video using math link textbook about pythagorean relationship.

## Monday, November 15, 2010

### Finding Side Lengths

from second base to home plate? How many different strategies can

you develop?Determine the length of leg s of the

right triangle

p2 + q2 = r2

p2 + 122 = 152

p2 + 144 = 225

p2 + 144 - 144 = 225 - 144

p2 = 81

p = √

___

81

p = 9

169y2 = 194y2

Give your answer to the nearest tenth of

a centimetre.

85 square rooted=9.2