In Grade 7, I learned that integers were whole numbers that were positive and negative. They could be represented using integer chips and a number line.
Find zero pairs for the following integers.
-6 +6
+10 -10
19 -19
-16 +16
-11 +11
+14 -14
63 -63
Integers ala Grade 7
have 4 owe 4
(+4) + (-4) = 0
Brackets are training wheels.
Standard form:
+4 -4
4-4 <--- pure standard form
Questions:
-3 - (-7) = +4
-3 - 7 = -10
3 - 7 = -4
3 + 7 = +10
-3 + 7 = +4
Chapter 2
Multiplying Integers
Sign Rule:
Even= when you have an even number of n
egative factors the product is POSITIVE.
Odd= when you have an odd number of negative factors the product is NEGATIVE.
(+2) x (+3) = +6
means 2 groups of (+3)
(+2) x (-3) = -6
means 2 groups of (-3)
(-2) x (+3) = -6
means remove 2 groups of (+3)
(-2) x (-3) = +6
means remove 2 groups of (-3)
Dividing Integers
How many groups of ___ are in ___?
How many __'s go into __?
Partative Division - making parts or groups
6 ÷ 2 = 3
How many groups of 2 are in 6?
How 2's go into 6?
-6 ÷ (-2) = 3
How many groups of (-2) are in -6?
How many (-2)'s go into -6?
Quotative Division - sharing with groups
(-6) ÷ 2 = -3
share groups
When both integers are the same you can use partative and quotative.
(+15) ÷ (+3) = (+5) or (-15) ÷ (-3) = (-5)
You can use multiplicative inverse to help solve 6 ÷ (-2) by finding the answer which is (-3) and switching it with (-2) making the question 6 ÷ (-3) and the answer would be (-2).
Order of Operations with Integers
Brackets
Exponents
Division
Multiplication
Addition
Subtraction
Solve this question:
(+5) x (-3) + (-6) ÷ (+3) =
[(+5) x (-3)] + [(-6) ÷ (+3)] =
(-15) + (-2) =
(-17)
Here's a link about integers.
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