*Chapter 1: Grade 7 Integer Review*

In Grade 7, I learned that integers were whole numbers that were positive and negative. They could be represented using integer chips and a number line.

Find zero pairs for the following integers.

-6 +6

+10 -10

19 -19

-16 +16

-11 +11

+14 -14

63 -63

Integers ala Grade 7

have 4 owe 4

(+4) + (-4) = 0

Brackets are training wheels.

Standard form:

+4 -4

4-4 <--- pure standard form

Questions:

-3 - (-7) = +4

-3 - 7 = -10

3 - 7 = -4

3 + 7 = +10

-3 + 7 = +4

*Chapter 2*

*Multiplying Integers*

*Sign Rule*:

Even= when you have an even number of

*n**egative*factors the product is POSITIVE.

Odd= when you have an odd number of

*negative*factors the product is NEGATIVE.(+2) x (+3) = +6

means 2

*groups of*(+3)(+2) x (-3) = -6

means 2

*groups of*(-3)(-2) x (+3) = -6

means

*remove*2 groups of (+3)(-2) x (-3) = +6

means

*remove*2 groups of (-3)

*Dividing Integers*

How many groups of ___ are in ___?

How many __'s

*go into*__?Partative Division - making parts or groups

6 ÷ 2 = 3

How many groups of 2 are in 6?

How 2's go into 6?

-6 ÷ (-2) = 3

How many groups of (-2) are in -6?

How many (-2)'s go into -6?

Quotative Division - sharing with groups

(-6) ÷ 2 = -3

share groups

When both integers are the same you can use

*partative*and*quotative.*(+15) ÷ (+3) = (+5) or (-15) ÷ (-3) = (-5)

You can use

*multiplicative inverse*to help solve 6 ÷ (-2) by finding the answer which is (-3) and switching it with (-2) making the question 6 ÷ (-3) and the answer would be (-2).

*Order of Operations with Integers*

**B**rackets

**E**xponents

**D**ivision

**M**ultiplication

**A**ddition

**S**ubtraction

Solve this question:

(+5) x (-3) + (-6) ÷ (+3) =

[(+5) x (-3)] + [(-6) ÷ (+3)] =

(-15) + (-2) =

(-17)

Here's a link about integers.

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