*Chapter 1*Grade 7 integer review

In grade 7, we learned about integers as being only represented as whole numbers that could be either posative or negative. We learned how to represent them by using integer chips and number lines. You can also make zero pairs with an even amount of posative integers and negative integers.

Find zero pairs for the following integers:

In grade 7, we learned about integers as being only represented as whole numbers that could be either posative or negative. We learned how to represent them by using integer chips and number lines. You can also make zero pairs with an even amount of posative integers and negative integers.

Find zero pairs for the following integers:

Integers in Grade 7

+4 is like saying you have 4 and -4 is like saying you owe 4.

In grade 7 we wrote integers using brackets ex. (+4) + (-4), these are just "training wheels", the actual standard form is written like this: +4-4 and the pure standard form is written like this: 4-4.

10-(-4) you are removing the negative part of the zero pair.

-3-2 is not subtracting, rather you have to add the negative integer.

Here are some questions:

1. -3-(-7)=+4

4.3+7=10

*Chapter 2: Multiplying Integers*Here is how I multiplied these integers:

1.2x3=6

2. 2x(-3)=-6

3. -2x(+3)=-6

4.(-2)x(-3)=+6

*Chapter 3: Dividing Integers*There are two different types of division: Partative and quotative. Partative division is when you know the number of groups but what you are trying to find is the number of items in that particular group.

Ex.

1. 6/2=3

2. -6/-2=+3

Quotative Division is the oposite of partative divisiong, you have to try and find the number of groups.

Ex.

-6/2=(-3)

There are some sign rules you may need to keep in mind for multiplying and dividing integers: When you are dividing two integers that are the same, the answer will be posative. However, if you are dividing two integers that are different, the answer will be a negative integer.

*Chapter 4: Order of operations with integers*(+5) x (-3) + (-6) ÷ (+3)=

When solving this problem we will have to apply the BEDMAS rules.

(+5)x(-3)+(-6)/(+3)=

(-15)+-6/(+3)=

-15+-2=-13

Sorry, I can't leave a video, my internet won't let me :(

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